(5分)设z=2+i1+i2+i5,则¯z=( )A.1−2i B.1+2i C.2−i D.2+i答案:B分析:先对z进行化简,再根据共轭复数概念写出即可.解:∵i2=−1,i5=i,∴z=2+i1+i2+i5=2+ii=1−2i,∴¯z=1+2i.故选:B.点评:本题考查了复数的运算及共轭复数的概念,属简单题.